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Top Foundations-of-Computer-Science Test Questions Answers | High-quality Foundations-of-Computer-Science Valid Braindumps Sheet: WGU Foundations of Computer Science
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WGU Foundations of Computer Science Sample Questions (Q57-Q62):
NEW QUESTION # 57
Which type of files are meant to be inaccessible to standard users, but can be critical in terms of functionality?
- A. System files
- B. Extension files
- C. Log files
- D. Backup files
Answer: A
Explanation:
Operating systems contain many files that are essential for booting, hardware support, security enforcement, and core services. These are generally referred to assystem files. Textbooks explain that system files are often protected by permissions and special attributes because accidental modification or deletion could destabilize the OS, break device drivers, prevent applications from running, or even stop the machine from booting.
Therefore, standard (non-administrator) users are typically restricted from accessing or altering them, and the OS may hide them by default to reduce the risk of user error.
Examples include kernel-related components, shared libraries, driver files, configuration databases, and critical service executables. Modern OS designs enforce protection through user accounts, access control lists, and privilege separation. This ensures only trusted processes and administrators can change system-critical components.
Log files record events and are sometimes protected, but many logs are readable by users or administrators depending on policy; they are not necessarily "meant to be inaccessible" in the same strict sense. Backup files are important for recovery but are not inherently system-critical for day-to-day operation, and their accessibility depends on organizational policy. "Extension files" is not a standard category; file extensions describe formats rather than a protected functional class.
Thus, the files intended to be inaccessible to standard users yet critical for functionality are system files, reflecting core OS security principles such as least privilege and integrity protection.
NEW QUESTION # 58
What is the purpose of the pointer element of each node in a linked list?
- A. To indicate the current position
- B. To store the data value
- C. To keep track of the list size
- D. To indicate the next node
Answer: D
Explanation:
In a singly linked list, each node is a small record that typically contains two main parts: a data field and a pointer field. The data field stores the actual value being kept in the list. The pointer field stores the address or reference of another node. The pointer element's purpose is to connect one node to the next by indicating where the next node is located in memory. This is essential because linked-list nodes are not stored in contiguous memory locations the way array elements are. Nodes may exist anywhere in memory, and the pointer is what preserves the logical sequence of the list.
This design supports efficient structural changes. For traversal, a program starts at the head node and repeatedly follows the pointer to reach subsequent nodes. For insertion, a new node can be added by adjusting a small number of pointers instead of shifting many elements, as would be required in an array. For deletion, the list can "skip over" a node by updating the pointer in the previous node to reference the node after the removed one. The end of the list is typically represented by a null pointer value, signaling there is no next node.
Keeping track of list size or current position is not the responsibility of each node's pointer field; these are usually handled by separate variables or computed during traversal.
NEW QUESTION # 59
How can someone subset the last two rows and columns of a 2D NumPy array?
- A. array[-1:, -1:]
- B. array[:, -2:]
- C. array[-2:, -2:]
- D. array[-2:, :]
Answer: C
Explanation:
NumPy slicing uses the same start/stop rules as Python sequences, and it also supports negative indices to count from the end. In a 2D array, slicing is written as array[rows, columns]. To get thelast two rows, you use
-2: in the row position, meaning "start two rows from the end and go to the end." Similarly, to get thelast two columns, you use -2: in the column position. Combining these gives array[-2:, -2:], which selects the bottom- right 2×2 subarray.
Option A, array[-2:, :], selects the last two rows butall columns, so it is not restricted to the last two columns.
Option D, array[:, -2:], selects all rows but only the last two columns. Option B, array[-1:, -1:], selects only the last row and the last column, producing a 1×1 (or 1×1 view) subarray, not a 2×2.
This kind of slicing is widely taught because it is essential for matrix operations, extracting submatrices, working with sliding windows, and manipulating image or time-series data where "take the last k observations/features" is common. Negative indexing reduces errors and makes code clearer, especially compared with computing explicit indices like array[rows-2:rows, cols-2:cols].
NEW QUESTION # 60
What Python code would return the value 2 from np_2d, where np_2d = np.array([[1, 2, 3, 4], [10, 20, 30,
40]])?
- A. np_2d[0,1]
- B. np_2d[2, 0]
- C. np_2d[2]
- D. np_2d[0,1][1]
Answer: A
Explanation:
NumPy arrays support multi-dimensional indexing using a comma-separated index tuple. For a 2D array, the first index selects the row and the second index selects the column. With np_2d = np.array([[1, 2, 3, 4], [10,
20, 30, 40]]), row 0 is [1, 2, 3, 4]. Within that row, column 1 is the second element, which is 2. Therefore, np_2d[0, 1] returns 2.
Option A is incorrect because np_2d[0,1] already produces a scalar (an integer), and indexing a scalar again with [1] is invalid. Option C, np_2d[2], attempts to access the third row, but this array has only two rows (indices 0 and 1), so it would raise an index error. Option D, np_2d[2, 0], also references a non-existent third row and would error.
This indexing rule is foundational in array-based computing: it provides direct access to elements without loops and supports efficient numerical computation. Understanding row/column indexing is essential for slicing, broadcasting, and matrix operations taught in scientific computing curricula.
NEW QUESTION # 61
What is the method for changing an element in a Python list?
- A. Use square brackets and the equals sign
- B. Use parentheses and the plus sign
- C. Use the del keyword and the element's value
- D. Use curly brackets and the equals sign
Answer: A
Explanation:
In Python, a list is a mutable sequence, meaning its elements can be changed after the list is created. The standard textbook method for updating a specific element isindex assignment, which uses square brackets to select the position and the equals sign to assign a new value. For example, if nums = [10, 20, 30], then nums
[1] = 99 changes the element at index 1 from 20 to 99, producing [10, 99, 30]. This works because lists store references to objects and allow those references to be updated in-place.
Option B is incorrect because parentheses are used for function calls and tuples, and the plus sign typically performs concatenation (creating a new list) rather than modifying an existing element by position. Option C is incorrect because curly brackets denote dictionaries or sets, not lists. Option D is incorrect because del removes elements by index or slice (for example, del nums[1]), and it does not delete by "the element's value" unless you first find the index. Deleting is not the same as changing; deletion reduces the list's length and shifts later indices.
Index assignment is fundamental in list manipulation and appears in standard algorithms: updating counters, replacing sentinel values, editing collections, and implementing in-place transformations efficiently without allocating a new list.
NEW QUESTION # 62
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